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hii!!
here is ur answer!
if x=3 is one root then f(x) =0
9-6k-6=0
3-6k=0
6k=3
k=3/6
k=1/2
help others!
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Step-by-step explanation:
As x=3
put the value of x in equation:
x²-2kx-6=0
3²-2×3×k-6=0
9-6-6k=0
3-6k=0
-6k=-3
k=1/2
so, the value of k is 1/2
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