Question

plz solve this question​

Answer 1

Step-by-step explanation:

x-1/x=4

x^2-x/x=4

x=x^2-x/4

x^2+1/x = (x^2-x/4)^2

Answer 2

Answer:

18

Step-by-step explanation:

Given:

${x}^{} - \frac{1}{ x } = 4$

To find:

${x}^{2} + \frac{ {1}}{ {x}^{2} }$

Solution:

$x - \frac{1}{x} = 4$

Squaring both side

${(x - \frac{1}{x} )}^{2} = {4}^{2} \\ \\ {x}^{2} + \frac{1}{ {x}^{2} } - 2.x. \frac{1}{x} = 16 \\ \\ {x}^{2} + \frac{1}{ {x}^{2} } - 2 = 16 \\ \\ {x}^{2} + \frac{1}{ {x}^{2} } = 16 + 2 \\ \\ {x}^{2} + \frac{1}{ {x}^{2} } = 18$

Hence, the required value is 18.