Question

Plz solve this question

Answer 1

Answer:

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Answer 2

1/a + 1/b + 1/c = 1/(a+b+c)

=> 1/a + 1/b = 1/(a+b+c) -1/c

=> (b+a)/ab = {c - (a+b+c)/c(a+b+c)

=> (a+b)/ab = -(a+b)/(ac+bc+c²)

=> 1/ab = -1/(ac+bc+c²)

=> -ab = ac+bc+c²

=-c² = ab+bc+ca

Similarly we can show that

-b² =ab+bc+ca and -c² = ab+bc+ca

So a=b=c. since -a² = -b² = - c²

Then 1/a + 1/b + 1/c = 1/(a+b+c) => 3/a= 1/3a

=> 1/a⁵ + 1/b⁵ + 1/c^5 =3/a⁵ = (( 3/a )(1/a⁴)

= 1/3a × 1/a⁴ = 1/3a⁵ = 1/(a⁵ + b⁵ + c⁵)

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