Math, asked by ayushg5608, 10 months ago

plz solve. this question​

Attachments:

Answers

Answered by punit2508
0

Answer:

Step-by-step explanation:

If x³-6x²+ax+b is exactly divisible by x²-3x+2, then it will also be divisible by (x-1)(x-2)[Factors of x²-3x+2].

Therefor Putting X=1 in the equstion x³-6x²+ax+b-:

1-6+a+b = 0

a+b = 5 ---------eq(i)

putting X= 2 in the equation x³-6x²+ax+b-:

8-24+2a+b = 0

2a+b = 16-------------eq(ii)

On solving Eq 1 & 2

a=11

b=-6

Similar questions