plz solve. this question
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Step-by-step explanation:
If x³-6x²+ax+b is exactly divisible by x²-3x+2, then it will also be divisible by (x-1)(x-2)[Factors of x²-3x+2].
Therefor Putting X=1 in the equstion x³-6x²+ax+b-:
1-6+a+b = 0
a+b = 5 ---------eq(i)
putting X= 2 in the equation x³-6x²+ax+b-:
8-24+2a+b = 0
2a+b = 16-------------eq(ii)
On solving Eq 1 & 2
a=11
b=-6
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