Question

Plz solve this question​

Answer 1

$LHS = \frac{1 - \cos \theta }{1 + cos \theta} \\ = > \frac{1 - \cos \theta}{ 1 + cos \theta} \times \frac{1 - cos \theta}{1 - cos \theta} \\ = \frac{ {(1 -cos \theta) }^{2} }{1 - {cos}^{2} \theta } \\ = > \frac{1 + {cos \theta - 2cos \theta}^{2} }{ {sin}^{2} \theta } \\ = > \frac{1}{ {sin}^{2} \theta} + \frac{ {cos}^{2} \theta}{ {sin}^{2} \theta} - \frac{2cos \theta}{ {sin}^{2} \theta } \\ = > {cosec }^{2} \theta + {cot \: }^{2} </h2><p>\theta - 2cosec \theta \: cot \theta \\ = > {(cosec \theta - cot \theta)}^{2} = RHS$

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