Question

Plz solve this question

Answer 1

Hi there!

In right triangle PQR,

PR = x+2
RQ = x

By, Pythagoras theorem

PR² = PQ² + QR²

(x+2)² = PQ² + x²

x² + 4 + 4x = PQ² + x²

PQ² = 4x+4

PQ = √4(x+1)

PQ = 2√x+1

Now, ATQ

i) √x+1.cotΦ

√x+1.QR/PQ

√x+1.x/2√x+1

x/2

ii) √x³+x².tanϴ

√x³+x².QR/PQ

√x³+x².x/2√x+1

x²/2

iii) cosϴ

PQ/PR

2√x+1/x+2

HOPE IT HELPED ^_^