plz solve this question
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Q-2. (1) .....
AP=34
AM=30
PQ=??
∆AMP=90
SO,
AP^2=AM^2+PM^2. [ Theory of Pythagoras ]
(34)^2= (30)^2+(PM)^2
1,156 = 900+(PM)^2
1,156 -900=(PM)^2
256=(PM)^2
(PM)^2=256
PM=√256
PM= 16
PQ= 2PM
PQ= 2(16)
PQ=32
This is your answer.......
AP=34
AM=30
PQ=??
∆AMP=90
SO,
AP^2=AM^2+PM^2. [ Theory of Pythagoras ]
(34)^2= (30)^2+(PM)^2
1,156 = 900+(PM)^2
1,156 -900=(PM)^2
256=(PM)^2
(PM)^2=256
PM=√256
PM= 16
PQ= 2PM
PQ= 2(16)
PQ=32
This is your answer.......
Answered by
2
hope this will help u....
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