Math, asked by mmohitsingh557, 6 months ago

plz solve this question​

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Answers

Answered by swainmalayakumar37
0

Answer:

angle B=angle D

Step-by-step explanation:

in ∆ABC&∆DEF

AB/DE=BC/FD

->AB/ED=AC/EF

TO BE SIMILAR ∆ABC&∆DEF WE MUST HAVE

Angle B=Angle D

Answered by Anonymous
4

Given:

\sf\large : \to \dfrac{AB}{DE}  =  \dfrac{BC}{FD}

Find:

\sf\large : \to when  \: \triangle ABC \: and  \: \triangle DEF \: will \: be \: similar

Solution:

If two sides of a triangle are proportional to the corresponding two sides in another triangle, and their included angles are equal, then the two triangles are similar by SAS rule.

If \dfrac{AB}{DC} = \dfrac{BC}{FD}, then for two triangles ABC and DEF to be similar, the included angle must be equal. In this case, the included angles are \angleB and \angleD

Hence, the answer will be \angleB = \angleD

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