Question

plz solve this question​

Answer 1

Answer:

Let a=b

x^2+y^2=a^2

Step-by-step explanation:

hope it helps you

Answer 2

Step-by-step explanation:

(x²/a²) + (y²/b²) = 1 {a , b}

Solution:

(x²/a²) + (y²/b²) = 1

(x²b² + y²a²)/a²b² = 1

x²b² + y²a² = a²b²

In this question we have two arbitrary constants. So we can differentiate the given equation two times.

differentiate the given equation with respect to x

2 x b² + 2 y y' a² = 0

divide the whole equation by 2

x b² + y y' a² = 0 ------ (1)

again differentiate the given equation with respect to x

we are going to differentiate y y' using product rule

u = y v = y'

u' = y' v' = y''

formula for product rule:

d (u v) = u v' + v u'

= y y'' + y' (y')

= y y'' + (y')²

(1) b² + [y y'' + (y')²] a² = 0

b² + [y y'' + (y')²] a² = 0 ----- (2)

=

x y y'

1 y''+yy'

x (y'² + y y'') - y y' = 0

Therefore the required equation is x (y'² + y y'') - y y' = 0.