Math, asked by barsa1, 1 year ago

plz solve this question..............

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Answered by Kkashyap
2
Let the co-ordinate of vertices be (x1,y1),(x2,y2),(x3,y3) of A ,B and C respectively
Midpoint of AB =(1,2)=(x1+x2/2,y1+y2/2)=>x1+x2=2;y1+y2=4.(i)
Similarly x2+x3=0;y2+y3=2..(ii)
And x1+x3=2;y1+y3=0..(iii.)
Adding eq (I),eq(ii),eq(iii) we get
2(x1+x2+x3)=4=>x1+x2+x3=2..(IV)
And 2(y1+y2+y3)=6=>y1+y2+y3=3..(v)
From eq(I),(ii),(iii),(IV) and (v) we get
(x1,y1)=(2,1) ;(x2,y2)=(0,3) and (x3,y3)=(0,-1)
Hope it helps

barsa1: Thank you very much
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