plz solve this question
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let length be 5x and breadth be 12x
in rt triangle ABC
AB^2 +BC^2= AC^2
(5x)^2 +(12x)^2 = 26^2
25x2+144x2 = 676
169x2 =676
x2 = 676/169
x2 = 4
x = 2
so sode are 5x equal to 10
and 12x equal to 24
so perimater will be 68cm
in rt triangle ABC
AB^2 +BC^2= AC^2
(5x)^2 +(12x)^2 = 26^2
25x2+144x2 = 676
169x2 =676
x2 = 676/169
x2 = 4
x = 2
so sode are 5x equal to 10
and 12x equal to 24
so perimater will be 68cm
Doubt1:
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