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Given : A circle of radius 3 cm with centre O and a point P at a distance of 7 cm from O. Tn = a + (n – 1)d ∴ a4 = a + 3d = – 15 a9 = a + 8d = – 30 Subtract eq (2) from ...... 8 – 6 = 3.5 cm 2 Area of shaded region = Area of semi-circle – area (∆ ABC) = πr 2 1 – × AC × BC 2 2 22 5 5 1 1 1 × × × – ×3×4 = 7 2 2 2 2 = 275 –6 28 = 9.
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