Math, asked by hrishikashyap9876, 5 months ago

Plz solve this question ​

Attachments:

Answers

Answered by nikhilsram2004
4

Answer:

refer the above attachment

Attachments:
Answered by Anonymous
3

\huge\underline\mathcal\color{blue}{AnSWeR}

  = \frac{7}{3 - 2 \sqrt{2} }

 =  \frac{7}{3 - 2 \sqrt{2} }  \times  \frac{3 + 2 \sqrt{2} }{3 + 2 \sqrt{2} }

 =  \frac{7(3 + 2 \sqrt{2}) }{ {(3)}^{2} - {(2 \sqrt{2} )}^{2}    }

 =  \frac{7(3 + 2\sqrt{2}) }{9 -  ({2 }^{2} \times   { \sqrt{2} }^{2}) }

 =  \frac{7(3 + 2\sqrt{2} )}{9 - (4 \times 2)}

 =  \frac{7(3 + 2 \sqrt{2} )}{9 - 8}

 = \frac{7(3 + 2 \sqrt{2} )}{1}

 = 7(3+2 \sqrt{2})

Similar questions