Math, asked by neha475, 1 year ago

Plz solve this question

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Answered by yuvsingh1705
1
Area of rectangular part=l×b
=13×7=91m^2
Area of both semicircular part
=(πr^2)
=(22/7×3.5^2)=(38.5)
=38.5 m^2
Total area of park=38.5+91=129.5m^2
perimeter=2 (l+πr)
=2(13+22/7×3.5)
=2(13+11)=48m
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neha475: Sorry the answer is wrong
akhileshsharma2: check please it written right
yuvsingh1705: check it,its right
yuvsingh1705: please mark my answer as brainliest
akhileshsharma2: let anyone else gives the ans
yuvsingh1705: its right , check it again
akhileshsharma2: okay
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Answered by akhileshsharma2
1
total area of the garden=area of rectangular portion+,the sum of the areas of the pairs of semicircles

=(13x7)+(2x1/2x22/7x3.5x3.5)

=(91+38.5)=129.5m2
perimeter of the garden=2x length of rectangular portion+circumference of circle
=(2x13+2x22/7x3.5)
=(26+22)=48m is ur answer hope it will help you mark as brain list

neha475: Thanks your answer is correct mr akileshsharma
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