Plz solve this question
Attachments:
Answers
Answered by
1
Area of rectangular part=l×b
=13×7=91m^2
Area of both semicircular part
=(πr^2)
=(22/7×3.5^2)=(38.5)
=38.5 m^2
Total area of park=38.5+91=129.5m^2
perimeter=2 (l+πr)
=2(13+22/7×3.5)
=2(13+11)=48m
Hope it helps you ☺️ please mark my answer as brainliest and start following me
=13×7=91m^2
Area of both semicircular part
=(πr^2)
=(22/7×3.5^2)=(38.5)
=38.5 m^2
Total area of park=38.5+91=129.5m^2
perimeter=2 (l+πr)
=2(13+22/7×3.5)
=2(13+11)=48m
Hope it helps you ☺️ please mark my answer as brainliest and start following me
neha475:
Sorry the answer is wrong
check please it written right
check it,its right
please mark my answer as brainliest
let anyone else gives the ans
its right , check it again
okay
please mark my answer as brainliest and start following me
Answered by
1
total area of the garden=area of rectangular portion+,the sum of the areas of the pairs of semicircles
=(13x7)+(2x1/2x22/7x3.5x3.5)
=(91+38.5)=129.5m2
perimeter of the garden=2x length of rectangular portion+circumference of circle
=(2x13+2x22/7x3.5)
=(26+22)=48m is ur answer hope it will help you mark as brain list
=(13x7)+(2x1/2x22/7x3.5x3.5)
=(91+38.5)=129.5m2
perimeter of the garden=2x length of rectangular portion+circumference of circle
=(2x13+2x22/7x3.5)
=(26+22)=48m is ur answer hope it will help you mark as brain list
Thanks your answer is correct mr akileshsharma
Similar questions