Question

Plz solve this question!!!​

Answer 1

$\huge{ \underline{ \underline{ \mathfrak{ \color{magenta}{question}}}}}$

$\tt \frac{2x - 9}{3x + 4} = - \frac{1}{16}$

$\huge{ \red{ \underline{ \underline{ \mathfrak{ \color{orange}{answer}}}}}}$

$\tt \to \blue{x = 4}$

$\huge{ \color{aqua}{ \underbrace{ \underline{ \color{lime}{ \mathbb{✯꧁᭄⋆SoLuTiOn⋆᭄꧂✯ }}}}}}$

$\tt \to \frac{2x - 9}{3x + 4} = - \frac{1}{16}$

$\tt \to16(2x - 9) = - 1(3x + 4)$

$\tt \to32x - 144 = - 3x - 4$

$\tt \to32x + 3x = - 4 + 144$

$\tt \to35x = 140$

$\tt \to \: x = \frac{ \cancel{140}}{ \cancel{35}}$

$\tt\to \: \red{x = 4}$

Answer 2

4

2x-9 = -1

2x = -1+9

2x = 8

x = 8/2

x = 4

3x+4 = 16

3x = 16-4

3x = 12

x = 12/3

x = 4