Question

plz solve this question​

Answer 1

☆ Solution ☆

Given :-

• Base of triangle is 15 cm .
• Area of triangle is 0.9 cm² .

To Find :-

• The altitude ( height ) of triangle.

Step-by-Step-Explaination :-

Let height of triangle be x

As we know that :-

Area of triangle = 1/2 × base × height

Putting the respective value,

0.9 = 1/2 × 15 × x

0.9 × 2/15 = x

x = 0.9 × 2/15

x = 0.12

Hence,

The altitude of triangle is 0.12 cm.

Answer 2

GIVEN:

• Base of triangle=15cm
• Area of triangle=0.9cm²

TO FIND:

• Altitude of triangle.

ASSUMPTION:

Let us assume that length of altitude of triangle be x.

SOLUTION:

★Area of triangle=1/2×base×height

0.9cm²=1/2×15cm× x

0.9×2/15=x

0.12cm=x

So the altitude of triangle=0.12cm.

More formula to know!

• Area of rectangle=length×breadth
• Area of square=side²
• Area of circle=πr²
• Perimeter of rectangle=2(L+B)
• Perimeter of square=4×side
• Circumference of circle=2πr.