Question

plz solve this question​

Answer 1

Answer:

Ascending order:

-1/3,-4/3,-4/9

Answer 2

Given :

$\sf \: \dfrac{ - 1}{3} \: \: , \: \dfrac{ - 4}{9} \: \: , \: \: \dfrac{ - 4}{3}$

To find :

Ascending order

Solution :

First of all we need to know what is ascending order.

Ascending order , is a order in which given set of numbers are arranged in there increasing order { starting from Smallest number }

We are given fraction, so firstly we need to equate there denominator.

• Denominator are , 3 & 9
• So we need to find LCM of 3 & 9

3 = 3×1

9 = 3×3

• LCM of 3 & 9 = 9

$\sf \: \bullet \: \: \dfrac{ - 1}{3} \\ \sf \: multiply \: and \: divide \: by \: 3 \\ \sf \implies \: \dfrac{ - 1}{3} \: \: = \: \: \dfrac{ - 1 \times 3}{3 \times 3} \\ \sf \implies \:\dfrac{ - 1}{3} \: = \: \: \dfrac{ - 3}{9} \\ \\ \\ \sf \: \bullet \: \: \dfrac{ - 4}{3} \\ \sf \: multiply \: and \: divide \: by \: 3 \\ \sf \implies \: \dfrac{ - 4}{3} \: \: = \: \: \dfrac{ - 4 \times 3}{3 \times 3} \\ \\ \sf \implies \:\dfrac{ - 4}{3} \: = \: \: \dfrac{ - 12}{9} \\ \\ \\ \sf \bullet \: \frac{ - 4}{9}$

As we know the greater the value of negative number, the smaller it is

So this gives,

$\sf \: \: \dfrac{ - 12}{9} \: < \: \: \dfrac{ - 4}{9 \: } \: < \: \dfrac{ - 3}{9} \\ \\ \sf \implies \: \dfrac{ - 4}{3} \: < \: \: \dfrac{ - 4}{9 \: } \: < \: \dfrac{ - 1}{3}$

ANSWER :

$\sf \: Ascending \: \: order \: \: = \: \: \dfrac{ - 4}{3} \: < \: \: \dfrac{ - 4}{9 \: } \: < \: \dfrac{ - 1}{3}$