Question

plz solve this question ​

Answer 1

In the rhombus

∠ BAM =70

o

We know that the diagonals of a rhombus bisect at 90

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∠ AOM =90

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Now , in Δ AOM ,

∠ AOM + ∠ OMA + ∠ MOA =1800

90+∠ OMA +70=180

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∠OMA=180−160=20

o