Math, asked by prazeetachudal, 3 months ago

plz solve this question​

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Answered by suhani5937
0

Answer:

x=95°

hope it helps uh..

Answered by ajay8949
1

 \sf{In Fig. }

 \sf{EP || AK}

 \sf{∠KAP = ∠EPA} \: ( alternate  \:   angles)

 \sf{Since \:  ANEP  \: is  \: a \:  Cyclic \:  Quadrilateral}

 \:  \:  \sf {so}        \sf{\: ∠ENA  +  ∠EPA    = 180°}</p><p> \\      \sf {  100° + ∠EPA = 180°}</p><p> \\                      \boxed{  \sf{ ∠ EPA = 80°}}

 \sf{therefore, ∠KAP = ∠EPA = 80°}

</p><p> \sf {∠LAK +∠KAP +∠PAN = 180°} (linear  \: pair )</p><p>         \\  \sf{15° + 80° + ∠PAN = 180° }</p><p>                 \\ \sf { ∠PAN = 180° - 95°}</p><p>                   \\   \boxed{ \sf {∠PAN = 85° }}

 \sf{∠PAN + ∠PEN = 180°({cyclic \:  quadrilateral}})</p><p>            \\ \sf { x + 85° = 180° }</p><p>             \\  \sf { x = 180° - 85°}</p><p>            \\  \boxed{ \sf \green{  x = 95°}}

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