plz solve this question
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let he invested x amount in 11%p.a
abd (8100-x) in the 12%p.a
so according to question
2[(x×11)/100+(8100-x)×12/100]=1814
=>11x/100+(97200-12x)/100=907
=>-x+97200=90700
=>x=97200-90700=6500rs
so 8100-x=8100-6500=1600rs
hence he invested 6500 rupees for 11%p.a and 1600 rupees for 12%p.a
abd (8100-x) in the 12%p.a
so according to question
2[(x×11)/100+(8100-x)×12/100]=1814
=>11x/100+(97200-12x)/100=907
=>-x+97200=90700
=>x=97200-90700=6500rs
so 8100-x=8100-6500=1600rs
hence he invested 6500 rupees for 11%p.a and 1600 rupees for 12%p.a
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