Question

Plz solve this question......

Answer 1

ansss. s... z. z. zz. z.. z. z.......

Answer 2

(27)

Given : (x/a) = (y/b) = (z/c).

Let (x/a) = (y/b) = (z/c) = k(any constant)

= > x = ak, y = bk, z = ck.

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Now,

LHS = (x^3/a^3) + (y^3/b^3) + (z^3/c^3)

= (a^3k^3/a^3) + (b^3k^3/b^3) + (c^3k^3/c^3)

= k^3 + k^3 + k^3

= 3k^3.

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RHS = 3(ak)(bk)(ck)/abc

= 3k^3.

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LHS = RHS.

Hope this helps!