Math, asked by monikahemnani, 16 days ago

plz solve this question

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Answered by kshitijain1508
1

(a) 1

26 this is the probability

Answered by YaoiGod1
0

=> P(king) = 4/52

Probability of getting a diamond card

= 13C1/52 [ because there are 13 cards of a suit]

=> P( diamond ) = 13/52

Probability of getting a diamond and king

= 1C1/52 [ because out of 13 diamond cards only 1 is king ]

=> P(diamond and king) = 1/52

P( A U B ) = P(A) + P(B) - P(A & B) where '&' denotes intersection symbol.

Now P ( diamond or king ) = P(diamond) + P(king) - P(diamond and king)

=> P(diamond or king ) = 13/52 + 4/52 - 1/52

=> P(diamond or king ) = 16/52 = 4/13

Hope it helps !!!

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