Question

plz solve this question

Answer 1

1)Given:-Fair of first Km=Rs 15
fair for each addational km=Rs 8
Hence,Taxi fair for 1st km=15
Taxi fair for first 2 km=15+8=23
Taxi fair for first 3 km=23+8=31
Taxi fair for first 4 km=31+8=39
Hence the series formed is 15,23,31,39
Since here the terms continuously increasing by the same number 8,So the above list forms an AP

2)a)a=10 and d=10
Let the series be a1,a2,a3,a4.....
a1=a=10
a2=a1+d=10+10=20
a3=a2+d=20+10=30
a4=a3+d=30+10=40
Therefore the series will be 10,20,30,40...
First four terms of the AP is 10,20,30 & 40

3)2)
Ap is -5,-1,3,7...
first term of AP is -5
d=a2-a1=(-1)-(-5)
= -1+5=4
HOPE IT HELPS.