Math, asked by photons123, 1 year ago

plz solve this question

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Answered by Anonymous
15
 <b> <I>
Hey there !!


 \boxed{ See \: the \: attachment \: for \: your \: answer .}



 \large \boxed{ \mathbb{TRIGONOMETRY.}}



 \huge \bf \underline{ \mathbb{LHS = RHS.}}



✔✔ Hence, it is proved ✅✅.

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 \huge \boxed{ \mathbb{THANKS}}



 \huge \bf{ \# \mathbb{B}e \mathbb{B}rainly.}
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rosangiri28pfbc5r: hahahahahahahahab
photons123: gr8 answer
Answered by rosangiri28pfbc5r
6
(cos@ cosec@ - sin@ sec@)/(cos@+sin@)
= {(cos@/sin@)-(sin@/cos@)}/(cos@+sin@)}
= {(cos^2@-sin^2@)/sin@cos@}/ ( cos@+sin@)
= {(cos@-sin@)(cos@+sin@)}/sin@cos@(cos@+sin@)
= (cos@-sin@)/sin@cos@
= (1/sin@)-(1/cos@)
= cosec@-sec@ proved
I put @ in place of theta .It is easy to understand .Hope it helps you .
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