plz solve this question
Attachments:
Answers
Answered by
2
here mate here your ans.....
given... AC=AE, AB=AD &BAD=EAC
to prove... BC=DE
as, BAD=EAC
on adding DAC on both sides
BAD+DAC=EAC+DAC
=BAC=EAD
now, in∆ABC&∆DEA
AB=AD
A=A..... common
AC=AE
by SAS congruence rule
∆ABC~=∆DEA
by CPCT
BC=DE
hope it helps you
given... AC=AE, AB=AD &BAD=EAC
to prove... BC=DE
as, BAD=EAC
on adding DAC on both sides
BAD+DAC=EAC+DAC
=BAC=EAD
now, in∆ABC&∆DEA
AB=AD
A=A..... common
AC=AE
by SAS congruence rule
∆ABC~=∆DEA
by CPCT
BC=DE
hope it helps you
rakesh4860:
hello
Answered by
1
Answer:
Step-by-step explanation:
In triangles ABC and ADE
AB=AD (given)
angleBAD =angle WAX
Adding AngleDAC ON both sides
angle BAC=angle DAE
AC=AE (given)
By SAS congruence
TRIANGLE ABC IS congruent to TRIANGLE DAE
BC=DE (BY Cpct)
Similar questions