Question

plz solve this question​

Answer 1

Answer:

Step-by-step explanation:

LHS⇒sinA/1+cosA

⇒by rationalizing

sinA(1-cosA)/1-cosA(1+cosA)

⇒sina(1-cosA)/1-cos²a

⇒sina(1-cosA)/sin2a

⇒1-cosA/sina ⇒ LHS=RHS

                               PLEASE MARK AS BRAINLIEST

Answer 2

Rationalise by (1-cosA)

=) sona/1+cosA**1-cosA/1+cosa

=) sinA(1-cosA)/[1+cosa][1-cosA]

=) sinA(1-cosA)/1-cos²A

=) sinA(1-cosA)/sin²A [sinA/sin²A=sinA]

=)1-cosA/sinA