plz solve this question
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Now you can substitute the value of a and b and then find the length.
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here AC AND BD ARE MIDPOINTS THEN
AC=BD
i.e.;{(x1+x2)/2;(y1+y2)/2}=mid point
therefore
(-2+4/2;1+b/2)=(a+1/2;0+2/2)
(1;1+b/2)=(a+1/2;1)
(a;b)=(1;1)
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