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sami91:
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☺HEY MATE HERE IS YOUR ANSWER ☺
Given: Diameter of cylindrical pipe = 7 cm
Now, As water running in a cylindrical pipe is collected in a container at the rate of 192.5 litres per minute
∴Volume of water flows in 1 min = 192.5 Litres
⇒Volume of water flows in 1 hour = 192.5 × 60 × 1000 cm 3 ......(i)
Let the distance covered by water in 1 hour = l
Volume of water that covers the diameter of 1 hour = πr 2 l .....(ii)
From (i) and (ii), we get,
⇒ πr 2 l = 192.5 × 60 × 1000
∴ The distance covered by water in 1 hr = 3 km.
Thus, Rate of flow of water = 3 km/hr
Given: Diameter of cylindrical pipe = 7 cm
Now, As water running in a cylindrical pipe is collected in a container at the rate of 192.5 litres per minute
∴Volume of water flows in 1 min = 192.5 Litres
⇒Volume of water flows in 1 hour = 192.5 × 60 × 1000 cm 3 ......(i)
Let the distance covered by water in 1 hour = l
Volume of water that covers the diameter of 1 hour = πr 2 l .....(ii)
From (i) and (ii), we get,
⇒ πr 2 l = 192.5 × 60 × 1000
∴ The distance covered by water in 1 hr = 3 km.
Thus, Rate of flow of water = 3 km/hr
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