plz solve this question
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Answer:The value of A is 45° and the value of B is 15°.
Step-by-step explanation:
Tan(A+B)=√3
Tan(A-B)=1/√3
But we know tan60°=√3 and tan30°=1/√3.
Therefore,
Tan(A+B)=60° ----(1)
Tan(A-B)=30° ----(2)
Adding (1) and (2),
2A=90°
A=45°
Using A=45° in (1),
45°+B=60°
B=15°.
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2(x^2 + 1/x^2) - 9(x + 1/x) + 14=0
use identity: a^2 + b^2 = (a + b)^2 - 2ab
so then
(x^2 + 1/x^2) = (x + 1/x)^2 - 2(x)(1/x)
= (x + 1/x)^2 - 2
now
2[(x + 1/x)2 - 2] -9(x +1/x) +14=0
2(x +1/x)^2 - 4 - 9(x + 1/x) + 14=0
2(x + 1/x)^2 - 9(x + 1/x) + 10 =0
let (x + 1/x) = p
2p^2 - 9p + 10= 0
2p^2 - 4p - 5p + 10=0
2p(p - 2) - 5(p - 2) =0
(p-2) (2p - 5) = 0
p = 2 , 5/ 2
when p = 2
x + 1/x = 2 => x^2 + 1 = 2x
x^2 +1 - 2x = 0
x^2 +2 -1 - 2x=0
(x -1) (x -1) = 0
(x - 1)^2 = 0
x - 1 = 0 => x = 1 ans.
when p = 5/2
then x + 1/x = 5/2
2x^2 + 2 = 5x => 2x^2 - 5x + 2 =0
2x^2 - 4x - x + 2= 0
2x( x - 2) -1 (x - 2) = 0
(2x - 1) (x - 2) = 0
x = 1/2 , x = 2
hence, possible values of x
are 1, 1/2 and 2.
Answer: x = 1, 1/2, 2
use identity: a^2 + b^2 = (a + b)^2 - 2ab
so then
(x^2 + 1/x^2) = (x + 1/x)^2 - 2(x)(1/x)
= (x + 1/x)^2 - 2
now
2[(x + 1/x)2 - 2] -9(x +1/x) +14=0
2(x +1/x)^2 - 4 - 9(x + 1/x) + 14=0
2(x + 1/x)^2 - 9(x + 1/x) + 10 =0
let (x + 1/x) = p
2p^2 - 9p + 10= 0
2p^2 - 4p - 5p + 10=0
2p(p - 2) - 5(p - 2) =0
(p-2) (2p - 5) = 0
p = 2 , 5/ 2
when p = 2
x + 1/x = 2 => x^2 + 1 = 2x
x^2 +1 - 2x = 0
x^2 +2 -1 - 2x=0
(x -1) (x -1) = 0
(x - 1)^2 = 0
x - 1 = 0 => x = 1 ans.
when p = 5/2
then x + 1/x = 5/2
2x^2 + 2 = 5x => 2x^2 - 5x + 2 =0
2x^2 - 4x - x + 2= 0
2x( x - 2) -1 (x - 2) = 0
(2x - 1) (x - 2) = 0
x = 1/2 , x = 2
hence, possible values of x
are 1, 1/2 and 2.
Answer: x = 1, 1/2, 2
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