Math, asked by nazishhakhter31, 1 year ago

plz solve this question

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Answers

Answered by tavilefty666
1

Answer:The value of A is 45° and the value of B is 15°.

Step-by-step explanation:

Tan(A+B)=√3

Tan(A-B)=1/√3

But we know tan60°=√3 and tan30°=1/√3.

Therefore,

Tan(A+B)=60°  ----(1)

Tan(A-B)=30°   ----(2)

Adding (1) and (2),

2A=90°

A=45°

Using A=45° in (1),

45°+B=60°

B=15°.

So that you can understand it better I am attaching a pic of this solution.

And if you have any doubt feel free to ask in the comment section.

And if my answer helped you please mark me as brainliest.

Thank you.

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nazishhakhter31: I dont want this ques
nazishhakhter31: I want the above one
nazishhakhter31: plz solve that ques also
Answered by TheLostMonk
9
2(x^2 + 1/x^2) - 9(x + 1/x) + 14=0

use identity: a^2 + b^2 = (a + b)^2 - 2ab

so then

(x^2 + 1/x^2) = (x + 1/x)^2 - 2(x)(1/x)

= (x + 1/x)^2 - 2

now

2[(x + 1/x)2 - 2] -9(x +1/x) +14=0

2(x +1/x)^2 - 4 - 9(x + 1/x) + 14=0

2(x + 1/x)^2 - 9(x + 1/x) + 10 =0

let (x + 1/x) = p

2p^2 - 9p + 10= 0

2p^2 - 4p - 5p + 10=0

2p(p - 2) - 5(p - 2) =0

(p-2) (2p - 5) = 0

p = 2 , 5/ 2

when p = 2

x + 1/x = 2 => x^2 + 1 = 2x

x^2 +1 - 2x = 0

x^2 +2 -1 - 2x=0

(x -1) (x -1) = 0

(x - 1)^2 = 0

x - 1 = 0 => x = 1 ans.

when p = 5/2

then x + 1/x = 5/2

2x^2 + 2 = 5x => 2x^2 - 5x + 2 =0

2x^2 - 4x - x + 2= 0

2x( x - 2) -1 (x - 2) = 0

(2x - 1) (x - 2) = 0

x = 1/2 , x = 2

hence, possible values of x

are 1, 1/2 and 2.

Answer: x = 1, 1/2, 2

nazishhakhter31: thanks brother
TheLostMonk: Welcome :)
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