plz solve this question
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to find sum of coefficients of f(x)
we should find f(1)
put x =1 in equation
we get
(16-11+2) f(1)=2016
7 f(1)=2016
f(1)=2016/7=288
mkrishnan:
i know u should mark brainliest
but why f(1)=sum of coefficient
???
for any polynomial f(1) =a0+a1+a2+a3+.......+an
ok
give the mark him
Answered by
3
sum of coefficients = f(1) (think why?)
just x=1 therefore (16 -11 +2)f(1) = 2016
let f(x) = (a1)x^n + (a2)x^n-1 + (a3)x^n-2 ............ (an)x + an+1 where a1 , a2 , a3 .......an+1 are the t coefficients. f(1) = a1 + a2 +a3........ + an+1
just x=1 therefore (16 -11 +2)f(1) = 2016
let f(x) = (a1)x^n + (a2)x^n-1 + (a3)x^n-2 ............ (an)x + an+1 where a1 , a2 , a3 .......an+1 are the t coefficients. f(1) = a1 + a2 +a3........ + an+1
super explanation
thnku
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