plz solve this question
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according to the question the breadth of the walking region = X
as you can see there are four rectangles formed by the walking area
the length of two walking zones is equal to the length of the rectangle which is 16 centimetres
in the breadth of the rectangle there are two opposite of zones whose length is 10 - 2X where X is the breadth of the rectangular area
total area walking zones is equals to 120cm^2
area of 2 bigger rectangles forming length of the field = 2 × 16 × X
=32 X...................... eq 1
area of two smaller rectangles are
2×(10-2X)× X.........................eq 2
adding eq1 and eq2
we get
eq1 + eq2 = 120
32X+2×(10-2X)× X= 120
WE GET
4X^2 - 52X +120 =0
after solving this we get
X= 10,3
X = 10 is not possible because the breadth of the whole field is 10
therefore the breadth of the walking area is 3 metres
as you can see there are four rectangles formed by the walking area
the length of two walking zones is equal to the length of the rectangle which is 16 centimetres
in the breadth of the rectangle there are two opposite of zones whose length is 10 - 2X where X is the breadth of the rectangular area
total area walking zones is equals to 120cm^2
area of 2 bigger rectangles forming length of the field = 2 × 16 × X
=32 X...................... eq 1
area of two smaller rectangles are
2×(10-2X)× X.........................eq 2
adding eq1 and eq2
we get
eq1 + eq2 = 120
32X+2×(10-2X)× X= 120
WE GET
4X^2 - 52X +120 =0
after solving this we get
X= 10,3
X = 10 is not possible because the breadth of the whole field is 10
therefore the breadth of the walking area is 3 metres
sunidhi2295:
but the answer is 2m
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