Question

plz solve this question​

Answer 1

Answer:

The roots are α²β  and  αβ²

Step-by-step explanation:

α β are zeros of x²+bx+c

α+β=-b/a  αβ =c/a

let m and n are zeros of

a³x²+abcx+c³

Then

m+n=-abc/a³=-bc/a2=(-b/a)*(c/a)

m+n=(α+β)*αβ=α²β+αβ²---------------------(1)

mn=c3/a3=(c/a)³=(αβ)³=α³β³=(α²β)*(αβ²)-----------------(2)

From 1) and (2) we found

m=α²β,n=αβ²

So the roots are α²β  and  αβ²