Question

plz solve this question
(algebraic rational expression)
do homely
plz answer my questions first.​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

$= \frac{ {x}^{2} }{6( {x}^{2} - 9) }$

Step-by-step explanation:

$\frac{3x + 1}{x - 3} - \frac{(x - 3)}{3x + 9} - \frac{(5 {x}^{2} + 24x) }{2 {x}^{2} - 18 } \\ \\ = \frac{(3x + 1)(3x + 9) - {(x - 3)}^{2} }{(x - 3)(3x + 9)} - \frac{(5 {x}^{2} + 24x )}{2 {x}^{2} - 18 } \\ \\ = \frac{(9 {x}^{2} + 30x + 9) - ( {x}^{2} - 6x + 9)}{3( {x}^{2} - 9) } - \frac{(5 {x}^{2} + 24x) }{2( {x}^{2} - 9) } \\ \\ = \frac{ (\frac{8}{3} {x}^{2} + 12 x ) - ( \frac{5}{2} {x}^{2} + 12x )}{ {x}^{2} - 9} \\ \\ = ( \frac{8}{3} - \frac{5}{2} ) \times \frac{ {x}^{2} }{( {x}^{2} - 9)} \\ \\ = \frac{ {x}^{2} }{6( {x}^{2} - 9) }$

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