Question

plz solve this question

(algebraic rational expression)
do homely
plz answer my questions first.​

Answer 1

Answer:

$\frac{ {x}^{3} }{ {x}^{3} - x - 1}$

$\frac{x}{x - \frac{1}{x - \frac{x}{1 + x} } } \\ \\ = \frac{x}{x - \frac{1}{ \frac{x(1 + x) - x}{1 + x} } } \\ \\ = \frac{x}{x - \frac{1}{ \frac{x + {x}^{2} - x }{1 + x} } } \\ \\ = \frac{x}{x - \frac{(1 + x)}{ {x}^{2} } } \\ \\ =\frac{ {x}^{3} }{ {x}^{3} - x - 1}$

HOPE IT HELPS