Question

Plz Solve this Question & get more Point...

Plz answers Step by Step....
Don't Samping ​

Answer 1

Explanation:

➡️ distance travelled is total area of a velocity time graph

➡️ distance=area of both trapeziums

➡️ area of trapeziums = 1/2 × (parallel) × height

➡️1/2 × (2+4) ×4. + 1/2 × ( 2+4) ×2

➡️ 1/2 × 6 × 4 + 1/2 × 6 × 2

➡️ 12 + 6

➡️ 18 metres

so,

option (a) is correct

Answer 2

Answer:

Total distance covered = Area of 2 trapeziums .

☆ Area of first trapezium :-

here ,

• l ' = 2
• l" = 4
• height (h) = 4 .

$area = \frac{1}{2} (sum \: of \: parallel \: sides) \: h \:$

$= \frac{1}{2} (6).4$

$= 12 \: m \: .$

☆ Area of second trapezium :-

here ,

• l' = 2 .
• l" = 4 .
• h = 2 .

$area \: = \frac{1}{2} (sum \: of \: parallel \: sides).h \:$

$area \: = \frac{1}{2} (2 + 4).2$

$area \: = 6 \: m \: .$

therefore, total distance covered ,

= ( 12 + 6 ) m

= 18 m .

therefore, option A , 18 m .