Question

Plz solve this question and give the step by step solution.... Don't give irrelevant answers...

Answer 1

Answer:

LHS: $2sec^{2} x$-$sec^{4} x$-$2cosec^{2} x$+$cosec^{4} x$

        2(Sec^2x - Cosec^2x) + (Coesc^4x - Sec^4x)

 Take Sec^2x-cosec^2x as common

 =Sec^2x-cosec^2x(2-cosec^2x-sec^2x)        [ Since a^2-b^2=(a+b)(a-b)]

 =[(1+tan^2x)-(1+cot^2x)][2-(1+tan^2x)-(1+cot^2x)] [Since trigonometric identities}  

 =(tan^2x-cot^2x)(-tan^2x-cot^2x)

 =Cot^4x-tan^4x

 =RHS

Hence proved

Answer 2

Answer:

gm sis..

I m in 10th clss