Question

Plz solve this question...anyone from 9th class.. ..12b​

Answer 1

Step-by-step explanation:

4725= 3a 5b 7c

So a=3 , b =2 ,c= 1

a=3

b=2

c=1

I hope it will helps u

Answer 2

Answer:

Step-by-step explanation:

Given :

If, $4725 = 3^a5^b7^c$

Then,

Find :

i) values of a , b & c,

ii) the value of :

$2^{-a}3^b7^c$

Solution :

We know that,.

4725 = 3 × 3 × 3 × 5 × 5 × 7

⇒ 4725 = 3³ × 5² × 7

⇒ $4725 = 3^a5^b7^c = 3^3 \times 5^2 \times 7^1$

⇒ a = 3 , b = 2 , c = 1,.

ii) So,

To find :

$2^{-a}3^b7^c$

⇒ $2^{-a}3^b7^c =2^{-3} \times 3^2 \times 7^1$

⇒ $\frac{1}{2^3} \times 3^2 \times 7^1$

⇒ $\frac{1}{8} \times 9 \times 7 = \frac{63}{8}$