Question

plz solve this question correctly!
if u do i will mark your answer as brainliest answer​

Answer 1

Question

A man is twice as old as his son today. Ten years ago, he was thrice as old as his son. What is the man's age today?

Answer

40 years

$\rule{200}{1}$

Explanation

Let the son's age today be x years.

Then according to the given condition, man's age = 2x

Now, ten years ago, age of son = (x - 10) years

And, age of man = (2x - 10)

Given, the man's age was thrice the age of his son ten years ago

⇒ (2x - 10) = 3(x - 10)

⇒ 2x - 10 = 3x - 30

⇒ 3x - 2x = 30 - 10

⇒ x = 20 years

Since x = 20 years = present age of son, so present age of father would be 2x = 2 ×20 = 40 years.

Answer 2

Answer:

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