Question

plz solve this question don't scam ​

Answer 1

$\sf{\red{\huge{\boxed{\bold{Solution}}}}}$

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: $\sf\implies\: {\bold{ 2^{3x-5}\times a^{x-2} = 2^{x-2} \times a^{1+x } }}$

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• If a x b = c ; a = $\sf{\bold{\dfrac{c}{b}}}$

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: $\sf\implies\: {\bold{ \dfrac{ a^{x-2}}{ a^{1-x}} = \dfrac{2^{x-2}}{2^{3x-5}}}}$

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• If bases are equal then in division powers will subtract ⠀

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: $\sf\implies\: {\bold{ a^{x-2-1 + x} = 2^{x-2-3x+5} }}$

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: $\sf\implies\: {\bold{ a^{2x- 3} = 2^{-2x+3} }}$

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• Taking " - " minus as common . ⠀

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: $\sf\implies\: {\bold{ a^{2x-3} = 2^{-(2x-3)} }}$

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• $\sf{\bold{ a^{-1} = \dfrac{1}{a}}}$

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: $\sf\implies\: {\bold{ a^{2x-3} = ( \dfrac{1}{2})^{2x-3} }}$

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• If powers are equal with equal's too sign then bases will also be equal

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: $\sf\implies\: {\bold{ a = \dfrac{1}{2} }}$

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$\sf{\red{\boxed{\bold{a = \dfrac{1}{2}}}}}$