Question

Plz solve this question from class9 polynomials

Answer 1

Answer:

Step-by-step explanation:

as given : (2-a)^3+(2-b)^3+(2-c)^3-3(2-a)(2-b)(2-c)

=(2-a)^3+(2-b)^3+(2-c)^3=3(2-a)(2-b)(2-c)

=8+a^3-3(4-a)(2-a^2)+8+b^3-3(4-b)(2-b^2)+8+c^3-3(4-c)(2-c^2)=3(2-a)(2-b)(2-c)

=8+8+8+a^3+b^3+c^3+(-3(2-a)92-b)(2-c))-3(4-a)(2-a^2)-3(4-b)(2-b^2)-3(4-c)(2-c^2)

=24+(a+b+c)^3-3{(4-a)(2-a^2)+(4-b)(2-b^2)+(4-c)(2-c^2)}

=24+(6)^3-3{(8-4a^2-2a+a^3)+(8-4b^2-2b+b^3)+(8-4c^2-2c+c^3)}

=24+216-3{8-4a^2-2a+a^3+8-4b^2-2b+b^3+8-4c^2-2c+c^3}

=240-3{24+a(a^2-4a)+b(b^2-4b)+c(c^2-4c)-2a-2b-2c}

=240-3{24+a^3+b^3+c^3-4(a^2+b^2+c^2)-2a-2b-2c}

=240-3{24+a^3+b^3+c^3-4(a+b+c)^2}

=240-3{24+a^3+b^3+c^3-4(6)^2}

=240-3(24+(a+b+c)^3-144)

=240-3(24+(6)^3-144)

=240-3(24+72)

=240-3(96)

=240-288

=-48