Question

pLz solve this question guys

Answer 1

It is given that
diameter=63, radius=63/2
height=4m=4×100cm=400cm

Volume of one cylindrical pillar=
$\pi \times r {}^{2} \times h$
=22/7×63/2×63/2×400
=1247400cm^3
=1.2474m^3

Volume of 10 cylindrical pillars=1.2474×10
=12.474m^3

So, 12.474m^3 of concrete mixture would be needed to build 10 pillars

curved surface area of the pillar=
$2 \times \pi \times r \times h$
=2×22/7×63/2×400
=79200cm^2
area to be whitewashed=curved surface area
=79200cm^2
=7.92m^2

total area to be whitewashed=7.92×10
=79.2m^2

hope this helps you....
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