Question

plz solve this question ,i have posted this question more than 10 times but no one is answering properly so if you the answer then only post it , so that you will get marked as brainlist
thank you ​

Answer 1

Explanation:

part 1 - Ab - prependicular - root 3 ( pythagoras theorem)

sina= p/h

root3/2 = sina

sin a = 60

therefore 60 is sin

part 2 - if cosecA = 2

then cosec²A = 4 ( squaring both sides)

identity - 1 + cot²A - Cosec²A

1 + cot²a = 2

cot²a = 1

therefore 1 is answer

part 3 - if tanA - root8

then tan² a = 8

identity -

1+tan²a = sec²a

1+8 = sec²a

9 = sec²a

sec = 3 answer

part 4 - 2nd quadrant