Question

Plz solve this question ....
I will mark as brain list

Answer 1

I hope it will help u........ dear

Answer 2

Answer:

solve $x^{2} +4x-5$as

          $x^{2} +5x-x-5$

     =$x(x+5)-1(x+5)$

     =$(x-1)(x+5)$

now solve

$x^3-x\\x(x^2-1)\\x(x-1)(x+1)$

now

$\ \lim_{ x \to\ 1} x^2+4x-5/x^3-x\\\\\ \lim_{x \to\ 1} (x-1)(x+5)/x(x+1)(x-1)$

now $(x-1)$ disappears  and we get

$\lim_{x\to \ 1} (x+5)/x(x+1)$

now put value of x=1 in the equaton and solve as

         $(1+5)/1*(1+1)$

       =  $6/2$

       =  $3$