Plz solve this Question. It's urgent with full explanation. A driver applies brakes when he sees a child on a railway track,the speed of the train reduces from 54km/h to 18km/h in 5 seconds. What is the distance travelled by the train during this interval of time?
Answers
Answered by
2
First of all we will find the acceleration
a= (v-u)/t
converting the final and initial velocity to m/s
54km/h= 15m/s
18km/h= 5m/s
(5-15)/5= -2m/s
By using the (Position-Velocity Relation) equation, we have
2as= v^2-u^2
2*(-2)*s= (18)^2-(54)^2
-4s= 324-2916
-4s= -2592
s= -2592/(-4)
= 648m
The distance travelled by train during this interval of time= 648m
a= (v-u)/t
converting the final and initial velocity to m/s
54km/h= 15m/s
18km/h= 5m/s
(5-15)/5= -2m/s
By using the (Position-Velocity Relation) equation, we have
2as= v^2-u^2
2*(-2)*s= (18)^2-(54)^2
-4s= 324-2916
-4s= -2592
s= -2592/(-4)
= 648m
The distance travelled by train during this interval of time= 648m
PKY76:
wrong answer
explain how
It's wrong bro
then what's the correct answer?
Similar questions