plz solve this question it's very important..
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✨here is your answer ✨
let the length of wire is equal to 2Xcm
breadth = x cm
area of rectangle = lb
= 2x² cm²
:: it is given that in the same wire is convert it in the form of a circle sew circumference of circle will be equal to the perimeter of rectangle ::
perimeter of rectangle = circumference of circle
2πr = 2(2x+x)
r = 21x/22
area of rectangle = area of circle -104.5
2x² = π(21x/22)² - 104.5
63x²/22- 2x² = 104.5
19x²/22 = 104.5
so, x² = 11×11
x = 11cm
so, sides of rectangle =
x = 11(breadth)
2x = 22 (length)
let the length of wire is equal to 2Xcm
breadth = x cm
area of rectangle = lb
= 2x² cm²
:: it is given that in the same wire is convert it in the form of a circle sew circumference of circle will be equal to the perimeter of rectangle ::
perimeter of rectangle = circumference of circle
2πr = 2(2x+x)
r = 21x/22
area of rectangle = area of circle -104.5
2x² = π(21x/22)² - 104.5
63x²/22- 2x² = 104.5
19x²/22 = 104.5
so, x² = 11×11
x = 11cm
so, sides of rectangle =
x = 11(breadth)
2x = 22 (length)
samruddhi25:
thx yrrr
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