Question

Plz solve this question...it's very urgent


Thanks in advance

Answer 1

Answer:

option 1 is correct

derivative of log x = 1/x

Answer 2

=y=(log x)^3

Then,log on both side

=log y=log(log x)^3

=log y=3log(log x)

Diff. with respect to x.

=1/y×dy/dx=3/x(log x)+0

=1/y×dy/dx=3/x(log x)

=dy/dx=3y/x(logx)

=dy/dx=3(logx)^3/x(logx)

=dy/dx=3×(log x)^2×(log x)/x log x

=dy/dx=3×(log x)^2/x