plz solve this question
lesson 4 std 10 ssc
construction
Answers
Answer:
construction of a triangle when all sides are given is easy.
Regarding ∆ PQR
PQ = 3.2 cm
QR = 3.6 cm
PR = 7.2 cm
now we are in big trouble!!!!
PQ + QR = 3.2 + 3.6 = 6.8 < 7.2
PQ + QR < PR
this is violating the very basic condition for construction of a triangle. Hence, a triangle with these measurements cannot be made.
let us change PQ to 3.8 cm. (assuming you wrote 2 in place of 8 mistakenly)
our new dimensions are
PQ = 3.8 cm
QR = 3.6 cm
PR = 7.2 cm
now draw a horizontal line and mark QR = 3.6 cm on it.
from point Q make an arc of 3.8 cm radius using compass. Similarly, from point R, make an arc of 7.2 cm using compass such that it intersects the earlier made arc at some point. mark the point of intersection as P
Join PQ and PR and it is done!!!!!
Regarding ∆STU
given ∆PQR is similar to ∆STU and
PQ/ST = 5/4
ST = PQ*4/5
= 3.8*4/5
= 15.2/5
= 3.04 cm
similarly
PR/SU = QR/TU = 5/4
SU = PR*4/5
= 7.2*4/5
= 28.8/5
= 5.76 cm
TU = QR*4/5
= 3.6*4/5
= 14.4/5
= 2.88 cm
Now that we have measurement of all the sides of ∆STU, we can draw the triangle in same way as we did in case of ∆PQR.