Question

plz solve this question no 6 ​

Answer 1

Answer:

Step-by-step explanation:

$If \;\alpha\;\beta\;and\;\gamma\;are\;roots \;of\;an\;equation\;say\\ \\ax^3+bx^2+cx+d=0\\\\then\\\\\alpha\;+\beta+\;\gamma=-\frac{b}{a}\\\\\alpha\beta+\beta\gamma+\gamma\alpha=\frac{c}{a}\\\\\alpha\beta\gamma=-\frac{d}{a}\\\\now\;given\\\\\alpha=-2\\\beta=1\\\gamma=4\\\\the equation is\\\\x^3-3x^2-6x+8=0\\\\\alpha\;+\beta+\;\gamma=3\\\\\alpha\beta+\beta\gamma+\gamma\alpha=-6\\\\\alpha\beta\gamma=-8$

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