Question

plz solve this question of trigonometry ​

Answer 1

Explanation:

;

Hey mate;

As you asked for I put it solution for you question;

For this I used following identities;

Sin C - Sin D = 2 cos { (C+D)÷2} × sin (C-D) ÷ 2;

Sin C - Sin D = 2 cos { (C+D)÷2} × sin (C-D) ÷ 2;Cos C - Cos D = 2 sin {(C+D) ÷ 2} × sin (D-C ) ÷ 2;

Sin C - Sin D = 2 cos { (C+D)÷2} × sin (C-D) ÷ 2;Cos C - Cos D = 2 sin {(C+D) ÷ 2} × sin (D-C ) ÷ 2;Or

Sin C - Sin D = 2 cos { (C+D)÷2} × sin (C-D) ÷ 2;Cos C - Cos D = 2 sin {(C+D) ÷ 2} × sin (D-C ) ÷ 2;Or -2SinC+D/2.sinC-D/2

.

After that;

In last second step I took

alpha+beta/2

alpha+beta/2 as comman;

alpha+beta/2as comman;

in cosalpha+beta/2

alpha+beta /2as comman;

in

cosalpha+beta/2sinalpha+beta/2

;

Other identity used=cosx/sinx

=cot x;

Hope you understand Hit like;

Be brainly

Answer 2

Answer:

hey mate please refer to the attachment