Question

plz solve this question on a page and add it to the attachment​

Answer 1

Answer:

answer below but coudn't find y andz

Step-by-step explanation:

3x+14=2x+25

3x-2x=25-14

x=11

angle d= anglez

3y+5+24=y+9+angle acb

3y-y+29-9=angle acb

2y+20=angle acb

3y+5+24=y+9+2y+20

180-(4y+14)=180-4y-14

166-4y

166-4y=z

Answer 2

Answer:

The required values are x = 11, y = 15, z = 106.

Step-by-step-explanation:

In figure, □ABCD is a parallelogram.

• AB = ( 2x + 25 ) cm
• DC = ( 3x + 14 ) cm

We know that,

Opposite sides of parallelogram are congruent.

∴ AB = DC

⇒ 2x + 25 = 3x + 14

⇒ 25 - 14 = 3x - 2x

⇒ x = 11

Now, AB ∥ CD and AC is transversal,

By alternate angles property,

∴ m∠DCA = m∠BAC

⇒ y + 9 = 24

⇒ y = 24 - 9

⇒ y = 15

Now, in △ACD,

By angle sum property of triangle

∴ m∠A + m∠C + m∠D = 180°

⇒ ( 3y + 5 )° + ( y + 9 )° + m∠D = 180°

⇒ 3y + 5 + y + 9 + m∠D = 180

⇒ 4y + 14 + m∠D = 180

⇒ 4y + m∠D = 180 - 14

⇒ 4y + m∠D = 166

⇒ 4 * 15 + m∠D = 166

⇒ 60 + m∠D = 166

⇒ m∠D = 166 - 60

⇒ m∠D = 106°

We know that,

Opposite angles of parallelogram are congruent.

∴ m∠D = m∠B

⇒ 106° = z°

⇒ z = 106

∴ The required values are x = 11, y = 15, z = 106.